- Find $\theta(t)$ at an arbitrary time t for uniform circular motion. Present the answer in terms of $\omega$ and t.
- Find position vector r at time. Present the answer in terms of $R$ and unit vectors x and y.
- Find the formula for the position vector of a particle that starts with $ (that\:is, (x_ {0}, y_ {0}) = (0, R)) $ on the positive y axis and then constantly moves in $ \omega $. Show the answer in terms of R, $\omega$ ,t ,and unit vectors x and y.
The first part of the question aims to represent the position vector in terms of $\theta(t)$ and $R$. The second part of the question seeks to find $\theta(t)$ for an arbitrary time $t$ for circular motion. The third part of the question aims to find position vector $r$ at time $t$. The last part of the question seeks to find position vectors in terms of $\omega$, $R$, and $t$.
Position vectors are used to indicate the position of a particular body. Knowing the part of the body is essential for explaining the movement of the body. A position vector is a vector that represents the position or position of any point with respect to a datum such as an origin. Position vector always points to a specific topic from the source of this vector. For issues that move along a straight path, the position vector that matches the way is most helpful. The velocity of a point is equal to the velocity at which the magnitude of the vector changes over time, resulting in a vector placed along a line.
Expert Answer
Part (1): Position vector $r(t)$ as a function of angle $\theta(t)$ in terms of $R$ and $\theta(t)$ is shown as:
\[r(t)=R\cos(\theta t)\vec{i} +R\sin(\theta t)\vec{j}\]
Part(2): $\theta(t)$ for uniform circular motion at an arbitrary time $t$ in term of $\omega$ and $t$ is shown as:
\[\theta(t)=\omega t\]
Part(3): Position vector $r(t)$ at time $t$ in terms of the $R$ and position vector $x$ and $y$.
\[r(t)=R\cos(\omega t)\vec{i}+R\sin(\omega t)\vec{j}\]
Part(4): Position vector $r$ for a particle that starts on the positive $y$ axis and moves with constant $\omega$.
\[r=Ri\]
\[r y(t)=-R\sin(\omega t)\vec{i}+R\cos(\omega t)\vec{j}\]
Numerical Answers
(1)
Position vector in term of $R$ and $\theta(t)$ is calculated as:
\[r(t)=R\cos(\theta t)\vec{i} +R\sin(\theta t)\vec{j}\]
(2)
$\theta$ for uniform circular motion at an arbitrary time is shown as:
\[\theta(t)=\omega t\]
(3)
Position vector $r(t)$ at time $t$ in terms of the $R$ and position vector $x$ and $y$ is calculated as:
\[r(t)=R\cos(\omega t)\vec{i}+R\sin(\omega t)\vec{j}\]
(4)
Position vector $r$ for a particle is shown as:
\[r=Ri\]
\[r\;y(t)=-R\sin(\omega t)\vec{i}+R\cos(\omega t)\vec{j}\]
Example
-What is the position vector $r(t)$ as a function of angle $\theta(t)$.
-Find position vector $r$ at time.
Solution
(a): Position vector $r(t)$ as a function of angle $\theta(t)$ in term of $R$ and $\theta(t)$ is shown as:
\[r(t)=R\cos(\theta t)\vec{i} +R\sin(\theta t)\vec{j}\]
(b): Position vector $r(t)$ at time $t$ in term of the $\omega$ and $R$ is given as:
\[r(t)=R\cos(\omega t)\vec{i}+R\sin(\omega t)\vec{j}\]