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The roots for the given quadratic equation are x1 ≈ 2.46625 and x2 ≈ -1.21625. For solving the quadratic equation 4x² – 5x – 12 = 0 we apply the quadratic formula, this method is a steadfast solution strategy when facing any quadratic equation of the form ax² – bx – c = 0. Below we explain the detailed answer to solve the given quadratic equation.
Expert Answer
To solve the quadratic equation 4x² – 5x – 12 = 0, we can use the quadratic formula, which is:
x = (-b ± √(b² – 4ac)) / (2a)
Here, a, b, and c are coefficients from the equation, where a = 4, b = -5, and c = -12.
We start by calculating the discriminant (Δ):
Δ = b² – 4ac
Δ = (-5)² – 4×4×(-12)
Δ = 25 + 192
Δ = 217
The discriminant (Δ) is positive, indicating two distinct real solutions.
Using the discriminant, we apply the quadratic formula:
x = (5 ± √(217)) / 8
This gives us two solutions for x:
x₁ = (5 + √217) / 8
x₂ = (5 – √217) / 8
For a more precise calculation, we approximate √217:
√217 ≈ 14.73
Substituting this into the solutions, we get:
x1 ≈ (5 + 14.73) / 8
x1 ≈ 19.73 / 8
x1 ≈ 2.46625
and
x2 ≈ (5 – 14.73) / 8
x2 ≈ -9.73 / 8
x2 ≈ -1.21625
Numerical Result
So, the approximate solutions for the equation are:
x1 ≈ 2.46625 (or x1 ≈ 2.47 if rounded to two decimal places)
x2 ≈ -1.21625 (or x2 ≈ -1.22 if rounded to two decimal places)
Example
Solve the following quadratic equation: 3x² + 6x - 9 = 0
Solution
To solve the quadratic equation 3x² + 6x - 9 = 0
, use the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)
. Here, the coefficients are a = 3
, b = 6
, and c = -9
.
Calculate the discriminant (Δ):
Δ = b² - 4ac
Δ = 6² - 4*3*(-9)
Δ = 36 + 108
Δ = 144
Since the discriminant (Δ) is positive, there are two distinct real solutions.
Apply the quadratic formula:
x = (-6 ± √144) / (2*3)
This results in two solutions for x:
x₁ = (-6 + 12) / 6
x₁ = 1
and
x₂ = (-6 - 12) / 6
x₂ = -3
So, the solutions to the equation 3x² + 6x - 9 = 0
are x₁ = 1
and x₂ = -3
. These are the x-values where the parabola represented by the equation would intersect the x-axis.